(x^2)-(11.2x)+24=0

Solution for (x^2)-(11.2x)+24=0 equation:

(x^2)-(11.2x)+24=0

We add all the numbers together, and all the variables

x^2-(+11.2x)+24=0

We get rid of parentheses

x^2-11.2x+24=0

a = 1; b = -11.2; c = +24;
Δ = b2-4ac
Δ = -11.22-4·1·24
Δ = 29.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.2)-\sqrt{29.44}}{2*1}=\frac{11.2-\sqrt{29.44}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.2)+\sqrt{29.44}}{2*1}=\frac{11.2+\sqrt{29.44}}{2}
$